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edM	05-09-2005 11:17 AM

assigning a large float number in E notation

hi,

how do you assign a large flatoing point number in C, is the syntax below correct?

float number1 = 2.302E-12; //delcare & assign
.
.
.
.
printf("%f", number1);

when i went to print it out all i got was '0.000000'

thanks :)

enemorales

05-09-2005 12:03 PM

Code:

float number1 = 2.302E-12

Well, this is actually a very SMALL number: about 0.000000000002302, to be more precise. This is because you put a MINUS (E-12) ;). Did you mean 2.302E12? (Which i think it is also 2.302E+12)

Hko	05-09-2005 12:03 PM

Re: assigning a large float number in E notation

Quote:

Originally posted by edM
float number1 = 2.302E-12; //delcare & assign
[...]
printf("%f", number1);

when i went to print it out all i got was '0.000000'

printf()'s defaults to 6 digits after the decimal point for "%f " conversion. And 2.302E-12 is smaller than 0.000000, so it's rounded to zero.

Either printf if in E-notatation:

Code:

printf("%E\n", number1);

Or specify how much digits after the decimal point should be output (precision), e.g. to get 15 digits:

Code:

printf("%.15f\n", number1);

edM	05-09-2005 12:51 PM

enemorales yes i meant large as in small. :p

thanks both you, very helpful!

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