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Old 03-27-2005, 04:16 AM   #1
bahadur
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Registered: Apr 2004
Distribution: Linux Red Hat
Posts: 141

Rep: Reputation: 15
accessing variables inside a function


#!/bin/bash

extractor()
{
FILES=`ls -l |awk '/^-/ {print $9}'`
SUBDIR=`ls -l |awk '/^d/ {print $9}'`
}

looper()
{
for FIL in $FILES
do
permissions.sh $FIL $3
done

for DIR in $SUBDIR
do
echo " the permissions being passed to other script are $2"
permissions.sh $DIR $2
search.sh $DIR $2
done
}



echo " Processing the directory $1"
cd "$1"

extractor
looper
--------------------------------------------------------------------------------------------------------------------

when i try to pass the $3 in the looper function it is not able to acces the variable $3 .

why cant that function access that variable?
 
Old 03-27-2005, 04:41 AM   #2
acid_kewpie
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Registered: Jun 2001
Location: UK
Distribution: Gentoo, RHEL, Fedora, Centos
Posts: 43,385

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afaik the $3 would be the third parameter passed to that specific function. why not save $3 as a sane variable when the script starts? $perms=$3 etc...
 
  


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