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Old 05-27-2009, 01:03 AM   #1
iframe
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Sorting Rows of a file


Hi,

I have a file, data.csv, with n rows, each row containing 7 numeric entries, like:

x3, x5, x1, x4, x7, x2, x6
x11, x13, x14, x8, x10, x12, x9
... ... ... ... ... ... ...

My question is: How can I sort each row in ascending order and output the resulting sorted file to, say, data_sorted.csv and the entries are sorted like:

x1, x2, x3, x4, x5, x6, x7
x8, x9, x10, x11, x12, x13, x14
... ... ... ... ... ... ...

All values are integers.

Note: I don't want to sort by columns, I want to to sort by rows...

Thanks in advance?
 
Old 05-27-2009, 01:06 AM   #2
ghostdog74
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what have you tried.
 
Old 05-27-2009, 01:25 AM   #3
JulianTosh
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Code:
for i in $(cat /tmp/numbers.txt); 
do
  echo $i | tr "," "\n" | sort -n | tr "\n" "," | sed "s/,$//"
  echo
done

$ cat /tmp/numbers.txt
4,2,5,3,1,6
9,7,10,8,11
$ /tmp/testnumbers
1,2,3,4,5,6
7,8,9,10,11
$

Last edited by JulianTosh; 05-27-2009 at 01:27 AM.
 
Old 05-27-2009, 01:27 AM   #4
jdkaye
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If the resulting vertical alignment (columns) is of no interest to you then just about any programming language (unicon, perl, python, etc. etc.) could do this in 3 or 4 lines of code. I would convert each row into a list and then sort the list and print the result to an output file. csv files are text files and the output of the program would preserve the csv format so you could import that directly into the application you're using. I could write you the code if you wish.
Cheers,
jdk
 
Old 05-27-2009, 01:35 AM   #5
thangappan
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Logic

I am telling the logic which can be applied using any programming language.

=> open a original file in read mode
=> open a resultant file in append mode
=> Parse a file line b line
=> one line contains one row (it has 7 fields)
=> Store the line in one array
=> Using sort operation sort the fields and append into resultant file.
=> Close both the files.
 
Old 05-27-2009, 01:39 AM   #6
chrism01
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Post #3 won't work if there are spaces between the fields, as per OP. Need to start with
Code:
IFS="
"
ie a hard coded newline
 
Old 05-27-2009, 01:52 AM   #7
iframe
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Is this php?

Hi,

Thanks for your answer. Is this php code?...

Quote:
Originally Posted by Admiral Beotch View Post
Code:
for i in $(cat /tmp/numbers.txt); 
do
  echo $i | tr "," "\n" | sort -n | tr "\n" "," | sed "s/,$//"
  echo
done

$ cat /tmp/numbers.txt
4,2,5,3,1,6
9,7,10,8,11
$ /tmp/testnumbers
1,2,3,4,5,6
7,8,9,10,11
$
 
Old 05-27-2009, 01:56 AM   #8
thangappan
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Implemention in perl

In the above reply I have mentioned that logic.Using that logic the following code has been implemented.

Perl Code:

my ($FH,$RH);
open ($FH,"<csvfile") or die "Can't open a file:$!\n";
open ($RH,">>outputfile") or die "Can't open resultant file:$!\n";

my (@sfields,@fields,$string);

while(<$FH>){
chomp;
@fields = split(/,/,$_);
@sfields = sort { $a <=> $b } @fields;
$string = join(",",@sfields);
print $RH "$string\n";
}
close($FH);
close($RH)

Input:
+ cat csvfile
4,2,5,3,1,6
9,7,10,8,11

Output:
+ cat outputfile
1,2,3,4,5,6
7,8,9,10,11

Last edited by thangappan; 05-27-2009 at 02:01 AM. Reason: I missed out join() function
 
Old 05-27-2009, 01:59 AM   #9
JulianTosh
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sorry, I didnt specify an interpreter... it's bash code.
 
Old 05-27-2009, 02:00 AM   #10
iframe
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Sorting rows of a file

I have tried bash sort -n, but it sorts the file by columns...

Quote:
Originally Posted by ghostdog74 View Post
what have you tried.
 
Old 05-27-2009, 02:08 AM   #11
iframe
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Registered: Mar 2007
Posts: 15

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Would be great if you help me with a bash script...

I have tried:

while read line
do
sort -n
echo "$line"
done < "$file"

but desn't work....

Quote:
Originally Posted by jdkaye View Post
If the resulting vertical alignment (columns) is of no interest to you then just about any programming language (unicon, perl, python, etc. etc.) could do this in 3 or 4 lines of code. I would convert each row into a list and then sort the list and print the result to an output file. csv files are text files and the output of the program would preserve the csv format so you could import that directly into the application you're using. I could write you the code if you wish.
Cheers,
jdk
 
Old 05-27-2009, 02:11 AM   #12
iframe
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Registered: Mar 2007
Posts: 15

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yup, thanks, i figured it out...
 
Old 05-27-2009, 02:16 AM   #13
iframe
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Registered: Mar 2007
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Spaces are not relevant, since I can use
cut -d, --output-delimiter=" " \
-f1-7 file.csv > new.csv

Quote:
Originally Posted by chrism01 View Post
Post #3 won't work if there are spaces between the fields, as per OP. Need to start with
Code:
IFS="
"
ie a hard coded newline
 
Old 05-27-2009, 02:26 AM   #14
ghostdog74
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if you have Python
Code:
#!/usr/bin/env python
def numeric_compare(x, y):
    return int(x[1:])-int(y[1:])

for line in open("file"):
    line =line.strip().split(", ")
    line.sort(cmp=numeric_compare)
    print ','.join(line)
output
Code:
# ./test.py
x1,x2,x3,x4,x5,x6,x7
x8,x9,x10,x11,x12,x13,x14
 
Old 05-27-2009, 03:06 AM   #15
PMP
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And if you have perl
do this :-)

cat test.txt
1,5,7,8,3,6
10,34,67,1,2,0,5

command line
perl -e 'while(<>){chomp; my @sorted = sort { $a <=> $b } split(",", $_); print join (",", @sorted); print "\n"}' test.txt
1,3,5,6,7,8
0,1,2,5,10,34,67

Cheers
 
  


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