Simple but can't figure it out: print or store value from egrep statement

PelleP · 09-02-2014, 02:32 AM

Hi!

Quick q:

I want to filter out only the location from a file path. I.e. getting only the string /root/ from
the string /root/file.db .
I do this using regexp, no problem. So if I have the file path text string in a file I'm getting what I want using:

Code:

egrep '^(.*[\\\/])' /path/to/file

which returns
/root/file.db with /root/ in red color.

But how the h**l do I extract that into a variable? If I use awk with the same regexp it prints the whole line.

And

Code:

var=$(egrep '^(.*[\\\/])' /path/to/file)

also stores the whole line into var.

Regards,
Pelle

jensd · 09-02-2014, 04:27 AM

You can use dirname to do this:

Code:

dirname /root/test
/root

PelleP · 09-02-2014, 04:41 AM

That was a much easier way!

Thanks a lot!

/P