Quote:
Originally Posted by wakatana
So if i dont need to manipulate IFS how can i do this:
input:
Code:
-rw-r--r-- 1 marek marek 0 2009-07-31 20:37 01 - album - track001.mp3
-rw-r--r-- 1 marek marek 0 2009-07-31 20:37 02 - album - track002.mp3
-rw-r--r-- 1 marek marek 0 2009-07-31 20:37 03 - album - track003.mp3
-rw-r--r-- 1 marek marek 0 2009-07-31 20:37 04 - album - track004.mp3
-rw-r--r-- 1 marek marek 0 2009-07-31 20:37 05 - album - track005.mp3
-rw-r--r-- 1 marek marek 0 2009-07-31 20:37 06 - album - track006.mp3
-rw-r--r-- 1 marek marek 0 2009-07-31 20:37 07 - album - track007.mp3
-rw-r--r-- 1 marek marek 0 2009-07-31 20:37 08 - album - track008.mp3
-rw-r--r-- 1 marek marek 0 2009-07-31 20:37 09 - album - track009.mp3
desiret output
trackXXX.mp3
i foud this can be done with this but did not work for me
Code:
for jmeno in *.mp3
do
cp $jmeno /tmp/`echo $i | sed "s/\([0-9]\{2\}\).*/track0\1.mp3/"`
done
is this possible using bash and for loop, i am trying to learn something about bash scripting this is what i am intersted in |
You are not taking into account the fact that there are spaces in the paths. Do it this way:
Code:
ls -1 *.mp3 | while read jmeno
do
cp $jmeno /tmp/`echo $i | sed "s/\([0-9]\{2\}\).*/track0\1.mp3/"`
done
Only addressing the loop construction, not its contents.
