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Old 09-02-2004, 08:36 PM   #1
ust
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run script error


I try to run a new script on the RH linux shell , it always pop the sign "##4" to each line , but I can run the same script on other shell , what is wrong in my system ? please suggest , thx in advance.


____________________________

##4who -u
##4awk '{ print $6":"$7 }'
##4grep -v '\.'
_____________________________
 
Old 09-02-2004, 08:41 PM   #2
serz
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# are comments in bash scripting, so that won't work, at least in bash...
 
Old 09-02-2004, 09:08 PM   #3
ust
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I hv a line "#!/bin/bash" at the beginning of the script , but still not work , what can I do now ? please suggest , thx.
 
Old 09-03-2004, 09:38 AM   #4
serz
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Could you please post the whole script?

You need to remove those ###4...

Code:
#!/bin/bash

who -u
awk '{ print $6":"$7 }'
grep -v '\.'
 
Old 09-06-2004, 01:58 AM   #5
ust
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the script as below.
 
Old 09-06-2004, 02:01 AM   #6
ust
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#!/bin/bash

set -x
for user1 in `who -u | awk '{ print $6":"$7 }' | grep -v "\."| awk -F : '{ print
($1*60)+$2":"$3 }'`

do

time=`echo $user1 | awk -F ":" '{ print $1 }'`
pid=`echo $user1 | awk -F ":" '{ print $2 }'`

if [[ $time -gt 360 ]]
then
kill -9 $pid
fi
done
 
Old 09-06-2004, 10:54 AM   #7
ust
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what is wrong with the script ? please advise , thx
 
Old 09-09-2004, 08:44 AM   #8
ust
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I still can't hv the error , could suggest what is wrong with my script ? thx.
 
  


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