reversing a number
 

how to take a number from input
and reverse it


int sum=0,t=1;
char ch;
scanf("%c",&ch);
while(ch!='.')
{
sum=sum+(ch-'0')*t;
t=t*10;
scanf("%c",&ch);
}
printf("%d",sum);


the abvove code works with a '\n' (or) '.'
can i write a funtion tom reverse it with out using . or \n;



waiting for u r reply.......

Why not do this in Perl? :twocents:

#!/usr/bin/perl -w
use strict;
my $digit;
print "Enter number:";
$digit = <STDIN>;
chomp $digit;
print "Number = $digit\n";
$digit = (reverse $digit);
print "Reverse Number = $digit\n";

If want to cut this script down even more:

#!/usr/bin/perl -w
print "Enter number:";
$digit = <STDIN>;
chomp $digit;
$digit = (reverse $digit);
print "Reverse Number = $digit\n";