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Old 04-19-2003, 11:24 PM   #1
Registered: Feb 2003
Distribution: Slackware
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regular expression question

how would I grep (or perhaps sed?) a file for every line not starting with a certain phrase?
Old 04-20-2003, 12:01 AM   #2
Registered: Feb 2003
Distribution: Slackware
Posts: 78

Original Poster
Rep: Reputation: 15
nevermind. I used awk.

awk '$1 !~ /192.168.| {print $1}' access_log | more
Old 04-20-2003, 04:24 PM   #3
Registered: Apr 2003
Posts: 52

Rep: Reputation: 15
egrep -v "^192.168.|" access_log|more


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