Read the output from a pipe with bash ?
 

Hello

I want to read the output from a pipe with bash.

To read a normal parameter works good:
"myscript.sh abc"

myscript.sh
#!/bin/sh
echo $1;
echo $*;


But i want do this with a pipe:
"echo abc | myscript.sh"

All I get with Google was "Use C" or "Use perl".

Thanks in advance.
Fluppi

This might work for you:

echo "Test" | xargs somescript.sh

This is the content of somescript.sh:

#!/bin/sh
echo "------------------------------------------------------------------------------------"
echo " From within :" $1
echo "------------------------------------------------------------------------------------"

And this the happens when executed:

$ echo "Test" | xargs somescript.sh
------------------------------------------------------------------------------------
From within : Test
------------------------------------------------------------------------------------


Hope this helps.

Thanks you, it works!
But, with xargs its "not the real thing", I mean, it looks not so beautiful.

Do I really have to use C or Perl ?

Although I don't angree with the choice of words (I think xargs is very real and a very handy tool, but that's a very personal opinion ;) ), I can relate to the 'not so beautifull'.

You don't specify why the first part of the pipe cannot be started/read from within the script, any particular reason??

If incorporating the first part into the shellscript isn't possible, then you have to use C or Perl.