Printing specific lines of a file using script.

barunparichha · 05-19-2009, 09:35 AM

Hi,
I have text file with say 1000 lines.
And I want to display lines numbered 100, 203 and 297 using a script/command.
How can I do this ?

I can print a particular line using:
sed -n '100p' file1 (where file1 is input file).

With Thanks,
Barun Parichha

colucix · 05-19-2009, 09:47 AM

Just print other lines adding sed commands separated by semi-colon:

Code:

sed -n '100p;203p;297p' file1

pixellany · 05-19-2009, 09:47 AM

sed -n -e '100p' -e '203p -e '297p' filename

Beaten again!!!! colucix was faster and had the better answer........I am humbled.....

ghostdog74 · 05-19-2009, 09:50 AM

if you have Python

Code:

#!/usr/bin/env python
for n,line in enumerate(open("file")):
   if n+t1>299: break
   if n+1 in [100,203,297]:
       print line.strip()

for big files, better to quit iterating the file after 297th record is reached.

Code:

awk 'NR==100||NR==203||NR==297{print}NR>300{exit}'  file

colucix · 05-19-2009, 09:58 AM

using awk

Code:

 awk 'NR==100||NR==203||NR==297' file1

barunparichha · 05-19-2009, 10:53 PM

Hi colucix,
you have missed the file name in your command.

Barun Parichha

colucix · 05-20-2009, 12:31 AM

Quote:

Originally Posted by barunparichha

Hi colucix,
you have missed the file name in your command.

Barun Parichha

Right. Thanks. I've corrected my post.