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Old 10-26-2012, 05:51 AM   #1
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Not able to extract files.

Dear All,

i want to extract all the files from one folder and the all fine name contains space in it so it is not able to extract the files

for f in $FILES
  echo "Processing $f file..."
7za u -o/logs/isac/collation/data/logs1/ "$f"
and the file names are like

AEPLWEB1-Server - Copy_H20121026-070000464.log.7z
AEPLWEB1-Server - Copy_H20121026-060000462.log.7z
Old 10-26-2012, 06:14 AM   #2
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Try this
Old 10-26-2012, 06:15 AM   #3
Keith Hedger
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while read
    7za u -o/logs/isac/collation/data/logs1/ "$REPLY"
done < <(find /logs/isac/collation/data/server1 -iname "*.7z")
Old 10-28-2012, 04:20 PM   #4
David the H.
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chrism01's link is for reading text from a file and operating on the contents. That's not what the OP asked for.

And Keith's is really just a variation of the same technique, only it uses the input from find as the text source, and runs the commands on that list. It will probably work, unless the filenames themselves actually contain newlines, but I see nothing there that simple globbing can't handle already (and I would simply use find's -exec option instead of the loop anyway).

In fact, the OP's code should work just fine as it stands, as far as I can tell, and indeed I would've given pretty much that exact solution. The variable contains a globbing pattern which would expand when the for loop is executed, which it should be able to read correctly and run the sub-commands on.

The only way I can see it failing is if the "$f" variable were not quoted in the subcommands (which would allow word-breaking on the contents), or if "$FILES" was quoted in the outside loop (in which case the content would be seen as a single entry, an unexpanded glob). But the loop as posted doesn't show either of those errors.

If the posted loop is indeed the exact command that was run, then the OP needs to explain in exactly what way it's not working. What errors or output are you actually getting?

Last edited by David the H.; 10-28-2012 at 04:25 PM.
Old 10-29-2012, 10:45 AM   #5
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I think the OP is not clear enough for me to provide a solution.

To extract all 7zips in a directory you can let 7zip handle it:

7z x '*.7z'
But, I'm not sure that this is what the OP wants. I'm not sure anyone can be sure until a more concrete example and explanation are provided.


extract, space

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