[SOLVED] Identifying usernames having duplicate user-id in /etc/passwd file

zama · 03-02-2012, 04:01 AM

Hi All,

I am trying to find out all users in my /etc/passwd which has duplicate user-ids . e.g if there are two users having user-id of 0. It should display the username as well as the user-id. I tried the following:

awk -F: '{
count[$3]++;}END {
for (i in count)
print i, count[i];
}' passwd

It gives the duplicate user-ids and how many times they are occuring . I actually want the usernames to be displayed along with the duplicate user-ids similar like

zama 0
root 0
bin 100
nologin 100

Will be great if the solution is provided with awk asscociative arrays. Other methods are also fine.

Thanks in Advance

catkin · 03-02-2012, 06:10 AM

Code:

awk -F: '
{
    count[$3]++;
    name[$3] = name[$3] $1 " "
}
END {
    for (i in count)
        print i, count[i], name[i];
}' /etc/passwd