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Old 12-08-2012, 01:16 AM   #1
SeerKan
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Registered: Jan 2012
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Help with a small bash script


Hey guys,

I want to mention that I'm still a beginner at this so bear with me

I made a small script that will check the users and if the size is larger than, let's say 204800, it will print the user and then send an email with the report.

Everything works except the fact that the script prints all the users, not only the one's having the value larger than 204800

This is the script, any suggestions are welcome:

Code:
#! /bin/bash
#finding all users, checking folder size and sorting

/usr/bin/find /home -printf "%u %s\n" | /usr/bin/awk '{user[$1]+=$2}; END { if (user[i] -gt 204800) for( i in user) print i " " user[i]}' | /bin/sort -rn +1 -2 > /root/disk-usage.txt;
#cheking if there is something in disk-usage.txt
if ls /root/ | grep -q "disk-usage.txt"
then
    # send email containing the output of the file
   /bin/cat /root/disk-usage.txt | mail -s "Disk Usage Report" my@email.com

fi;

#delete txt file
rm -rf /root/disk-usage.txt
 
Old 12-08-2012, 05:31 AM   #2
Snark1994
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Registered: Sep 2010
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Distribution: Arch
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It is probably easier to just use

Code:
du -s /home/* | awk '{if($1 > 204800){print $0;}}' | sort -rn > /root/disk-usage.txt
'du' does all the counting for you, and then do the comparison. I think your awk might work if you put braces ("{" and "}") in it (currently, if you check the contents of /root/disk-usage.txt, then you can see it contains all users' usage, not the ones who have used too much), but it's probably simpler to use 'du' and then a smaller, clearer, awk command.

Hope this helps,
 
Old 12-08-2012, 05:49 AM   #3
SeerKan
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Registered: Jan 2012
Posts: 4

Original Poster
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That helped, thanks.
 
  


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