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Old 03-27-2002, 11:01 AM   #1
Fernandoch
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Registered: Mar 2002
Location: Spain
Distribution: Debian, Cent OS, RHEL
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Question GRUB problem in Linux Red Hat 7.2


I have 3 OS, Windows 98, Windows 2000 and Windows XP.

Here is how my two hard disks are divided:

Disk1:

C: Win98 (4 GB)

D: Windows 2000 Pro (4.5 GB)

E: Windows XP (8 GB)

And a lot of space left too in disk 1

Disk 2 is all empty. (20 GB)

I tried to install Red Hat Linux 7.2 in the second hard disk. I used the GRUB boot loader. Linux starts perfectly, but I cannot start my windows anymore!! Why is that??? Do you think it has something to do with the 1024 cylinder rule? Before I installed Linux I could choose among the different Windows I have

Look what it gives me when I select to start windows:
--------------------------------------------------------------------------
Booting 'DOS'
rootnoverify (hd1,4)
chainloader +1

Invalid system disk

Replace the disk, and then press any key
----------------------------------------------------------------------------

What should I do to make it work???? I really want to start working with Linux!!!!
 
Old 03-28-2002, 04:07 AM   #2
linuxcool
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Registered: Jun 2001
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It appears that when you installed red hat that it installed grub in the MBR ( master boot record ) of disk 1. That's why you get grub instead of the boot loader for xp or win2000. The (hd1,4) is the partition hdb5. That's not on disk 1 where your windows os's are located.

Run this command fdisk -l /dev/hda and post the results here. Also, post a copy of your /boot/grub/grub.conf file. If you don't find grub.conf, look for menu.lst. Do you know which boot loader , xp or win2000, was being used before you installed linux?
 
Old 03-28-2002, 03:26 PM   #3
Fernandoch
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Registered: Mar 2002
Location: Spain
Distribution: Debian, Cent OS, RHEL
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Linuxcool, what do all these commands do? And where should I type them? Well I don't know what boot loader it is. I installed windows 98, then 2000, then XP. So I guess it should be the boot of XP, no?
 
  


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