filename escaping in bash
I have a file and its name includes special characters, for example: '"()$` $
I want to print a command which can be copy/pasted in a bash terminal, for example: ls '"()$` $
Obviously, this won't work, I need to escape that value.
What I'm using at the moment is the following function:
echo ''"'"'"()$` $'
Now if I run the printed echo command, it prints, as expected:
My question: Is there a more elegant or a better solution than my escape() function above? Ideally it would be an internal Bash command. For example, a function which would escape exactly the special characters, and nothing more, and would produce, for the example above: echo \'\"\(\)\$\`\ \ \$ instead of printing and having to use a gazillion quotes. ;)
In the Bash version of printf, %q quotes the argument in a way that can be reused as shell input.
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