command to print the last field
 

Hi,

Is there a way to extract the last field?

Specifying the field number is causing problems using awk or cut as the input log file has the output specified in different lines at different places/fields. The only thing constant is the 'pathname' which always occurs at the end, which is what I want

Thanks a lot

D

Hi,

Is this what you are looking for: awk '{ print $NF }' infile

NF is special in awk, it tells you how many fields there are, using it as $NF will print the last field.

Hope this helps.

Thanks a lot...it helps

You're welcome :)

If this is issue is fixed, could you put up the solved flag (First post -> Thread Tools)?