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Old 08-29-2003, 09:57 AM   #1
odious1
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Registered: Jun 2003
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Can I compile a windows .exe?


I am taking a c++ where we are compiling our programs using visual c++. What I was wondering is there some way I can compile windows apps without the microsoft product? I installed cygwin on my pc thinking that would work and it may but there are no man pages unless I did something wrong. Or even better is there an app I can install on my RH machine that I can use.

This whole kernel/compiling/header thing is very confusing to me but I want to learn!

I appreciate any help
 
Old 08-29-2003, 10:14 AM   #2
deepsix
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http://rooster.stanford.edu/~ben/linux/crosshowto.php <---check this out hope it helps or at least puts you in the right direction
 
Old 08-29-2003, 11:06 AM   #3
iceman47
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As long as you don't write programs in windows that need windows libraries, you can compile c++ on GNU with g++.
 
Old 08-29-2003, 11:18 AM   #4
odious1
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I do not know if I am doing something wrong or not but I keep getting error messages when I tried g++ or 1386...gcc. They appear to be syntax errors but it compiled fine with the visual c++. Does this mean I am doing something wrong or do I need to try and fix the code for use with a differend compiler?
 
Old 08-29-2003, 11:20 AM   #5
iceman47
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You might be using libraries g++ doesn't have, can you post the source?
 
Old 08-29-2003, 11:46 AM   #6
odious1
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Thanks for the help. Don't laugh at my litte program, I am just learning. But anyway this thing did fine when I compiled it withe microsoft visual c++.

Thanks

#include <iostream.h>



char target1;
int target2;
short int target3;
long int target4;
unsigned int target5;
float target6;
double target7;
long double target8;

void main(void)
{

cout << "\nBytes of storage used by a character: "
<< sizeof(target1);

cout << "\nBytes of storage used by an integer: "
<< sizeof(target2);

cout << "\nBytes of storage used by a short integer: "
<< sizeof(target3);

cout << "\nBytes of storage used by a long integer: "
<< sizeof(target4);

cout << "\nBytes of storage used by an unsigned integer: "
<< sizeof(target5);

cout << "\nBytes of storage used by a float: "
<< sizeof(target6);

cout << "\nBytes of storage used by a double: "
<< sizeof(target7);

cout << "\nBytes of storage used by a long double: "
<< sizeof(target8) << '\n';
}
 
Old 08-29-2003, 12:36 PM   #7
iceman47
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First: main() really needs to return an integer so change this line: void main(void) into int main()

Second: compiles fine on my computer, maybe it's time to check how you actually compile the source.

if it's called test.c, do this: g++ -o test test.c
and if it's still not working, post the error output.
 
  


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