Can anyone please explain about "Function call interrupts" entry in /proc/interrupts?
In the /proc/interrupts file, there is one entry called the Function call interrupts.
Can anyone please explain to me how this interrupt is generated or what it does?
An example is shown in bold below.
Thanks!
$ cat /proc/interrupts
CPU0 CPU1
0: 7531 0 IO-APIC-edge timer
1: 2 0 IO-APIC-edge i8042
4: 2 0 IO-APIC-edge
6: 5 0 IO-APIC-edge floppy
7: 0 0 IO-APIC-edge parport0
8: 1 0 IO-APIC-edge rtc0
9: 0 0 IO-APIC-fasteoi acpi
12: 4 0 IO-APIC-edge i8042
14: 5175137 0 IO-APIC-edge ata_piix
15: 0 0 IO-APIC-edge ata_piix
16: 10030496 0 IO-APIC-fasteoi ohci1394, HDA Intel
17: 33884045 0 IO-APIC-fasteoi eth0
18: 0 0 IO-APIC-fasteoi uhci_hcd:usb4
21: 2710880 0 IO-APIC-fasteoi ehci_hcd:usb1, uhci_hcd:usb2
22: 0 0 IO-APIC-fasteoi uhci_hcd:usb3
23: 0 0 IO-APIC-fasteoi uhci_hcd:usb5
2299: 2586197 0 PCI-MSI-edge ahci
NMI: 0 0 Non-maskable interrupts
LOC: 173199773 171952935 Local timer interrupts
RES: 1503044 3046141 Rescheduling interrupts
CAL: 1360 2472 Function call interrupts
TLB: 546223 608397 TLB shootdowns
SPU: 0 0 Spurious interrupts
ERR: 0
MIS: 0
Last edited by cyclops.xmen; 12-02-2009 at 12:52 PM.
|