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Old 10-12-2006, 01:42 AM   #1
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Call One shell script from another shell script

Hi Everybody

I am new for Shell scripts in Linux.

I am using Slackware Linux 10.

I have two shell scripts and from i am calling with one argument.

can you anybody tell me how I call from

Thanks in advance.
Old 10-12-2006, 02:14 AM   #2
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Of course you need to specify the full path to if it is not in the same directory where is found.
Old 10-12-2006, 04:21 AM   #3
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Thanks for your help.

It is working if we call with out argument, but I want to pass one command line argument also release or debug

I will handle this argument in

Old 10-12-2006, 05:44 AM   #4
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or equivalently
performs "sourcing" of the 2nd script. This is similar to including and executing the code of as if it was inside (ie if defines functions, you can source in and then use those functions in
This is not the same as just calling from (like if you were calling an executable or any
other standard command like "ls", etc).
To do that, just call with it's parameter:
/path/to/ param1 param2 ...

Make sure that
1. is executable
2. has an appropriate path (unless it's in one of the directories of $PATH)

Catching's output can be done via backticks or similar syntax. Check the man pages of your shell for syntax details.
Old 10-12-2006, 06:15 AM   #5
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/root/Desktop/ debug

sleep 5

/root/Desktop/ release

exit 0

if [ "$#" -eq 1 ]; then

if [ "$ARG" = "release" ]; then

echo $ARG


if [ "$ARG" = "debug" ]; then

echo $ARG

That works in my box.


Old 10-13-2006, 03:59 AM   #6
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Thanks for your help

Now It is working.

Thankyou once again


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