Bash scripting, deleting an entry from a list

Dee-ehn · 04-06-2007, 02:09 AM

Hi,

In a bash script, I use the following line:

Code:

ls -al | awk {'print $1'}

.

Now I want to remove the first 3 lines from the list this outputs. How can I do that?

I figured I can use the tail command, but on certain input, tail seems to struggle (leading "-" characters).

TIA!

almatic · 04-06-2007, 03:40 AM

try this:

ls -al | awk {'print $1'} | sed -n '4,$p'

Dee-ehn · 04-06-2007, 06:15 AM

Quote:

Originally Posted by almatic

try this:

ls -al | awk {'print $1'} | sed -n '4,$p'

Thanks a lot, that really did the trick!!!