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Old 12-04-2011, 07:45 AM   #1
coss_cat
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Registered: Jul 2007
Location: Bucharest, Romania
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awk return an error that I don't know how to handle


Hello everyone,

I have an nasty message that I receive all the time and I have no idea how to cope with.
My application is to make a script that finds directories where there are lots and lots of files, which eat a lot of inodes, in order to delete them.
For this I used a simple "find / -name "*" -fls listfile.txt -type f" that writes to listfile.txt all normal files existing in the system.
After this I separate the last column that represent the full path to files (in the file intermediar.txt) and try to use them with awk. Whatever i try to do i get this error:

awk '{ printf ""$0"\n" }' intermediar.txt >> int2
awk: (FILENAME=intermediar.txt FNR=465244) fatal: not enough arguments to satisfy format string
`/home/cosscat/.mplab_ide/dev/beta7.12/var/cache/cnd/model/%2Fhome%2Fcosscat%2FMPLABXProjects%2FLED_mobila%2FLED_mobila.asm%2FLED_mobila.XN
^ ran out for this one


Any idea? I really need to use awk for this one. I tried different tricks with sed, but i am limited.

Thank you.
 
Old 12-04-2011, 07:56 AM   #2
David the H.
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Registered: Jun 2004
Location: Osaka, Japan
Distribution: Debian sid + kde 3.5 & 4.4
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Code:
printf ""$0"\n"
This is not the proper syntax for an awk printf statement. The first argument needs to be the format string, followed by a comma, and then the input string to be formatted.

Code:
printf "%s\n" , $0
Of course the above format string is just equal to the print command.

http://www.gnu.org/software/gawk/man...de/Printf.html

What is it exactly that you want the awk command to do, anyway? Could you give us an actual example of the input and desired output?

Finally, please use [code][/code] tags around your code and data, to preserve formatting and to improve readability.
 
1 members found this post helpful.
Old 12-08-2011, 03:34 PM   #3
coss_cat
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Hello,

Yes I will post the whole thing I intend awk to do, and explain the idea in full detail.

Thank you David.
 
Old 12-09-2011, 10:15 AM   #4
coss_cat
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Distribution: Ubuntu
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Talking

Hello,

Sorry for not being explicit from the start. Here is what I have to do:

I work on Unix based servers (I know this post should be under Unix/Solaris etc. but it's general thing, and my chances are higher here), and there are processes that periodically generate log files. The thing is that often there is no purging entry in crontab to automatically delete the old and obsolete files. This of course, in time even though there is plenty of space on HDD, eats all inodes, meaning no write can be done anymore (not to mention the very slow OS when this happens). So I made up a script to identify where exactly the folder containing lots and lots of files is located in order to further investigate. The script work just fine, but it is totally memory inefficient(so I need awk to replace part of it). Downwards is the script:


#!/bin/bash

echo "Start first phase. This will take a while ..."
find / -name "*" -type f -fls result.txt
# this phase literally searches all files on root file system and dumps full path to each one of them in result.txt. No fancy things here, just a find command
echo "First phase done. Second phase is starting. It also will take a while ..."
sed 's/^.*[0-9][0-9] \(\/.*\)\/.*$/\1/g' result.txt >> intermediar.txt
# the sed command here retains only the directory to where the file is situated. I used some regex to describe the pattern encountered on each line
echo "Last phase. Results are shown downwards:"
printf "\n\n\n\n"


#from now on what's done is a simple count of each occurrence of a distinct path (since in case a folder contains 100000 text files each file is printed
with it's full path in result.txt, it means that the path appears 100000 times in this file ... so it is counted). The thing is that the script accepts an
input variable which is the minimum number of files a folder should contain in order to be displayed.
#Well, what I need is to replace this counting part of the script with something awk based. I tried different approaches but failed. Indeed I should read
carefully the awk manual, but I ask for help this time, as i don't have sufficient time to improve my awk skills.
#Thank you in advance.

rm result.txt
min_val=$1
var="0"
suma="0"
for i in $(cat intermediar.txt)
do
var1=$i
if [[ $var == $var1 ]]
then
suma=$(($suma+1))
else
if (( $min_val <= $suma ));then
echo "$suma ---> $var"
printf "\n"
fi
var=$var1
suma="0"
fi

done


The thing with this script is that at third phase when loading all lines of result.txt "for i in $(cat intermediar.txt)" , the memory it eats goes of the scale, and for a server this is the last thing anyone would want.

Thank you in advance for your help

Last edited by coss_cat; 12-09-2011 at 10:17 AM.
 
  


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