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Old 04-26-2005, 12:52 AM   #1
dtra
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Registered: Nov 2004
Distribution: fc4
Posts: 104

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[php] accessing command line


hi all

i am writing a script for video uploads with conversion
just want to see if this is possible

PHP Code:
$flags ' -i /home/httpd/vhosts/example.com/httpdocs/temp/' $tempOrigVideo ' -ar 22050 /home/httpd/vhosts/example.com/httpdocs/videos/' $uploadedVideo;

$execVideo '/usr/local/bin/ffmpeg ' $flags;
exec($execVideo); 
the script ends up looking like
"/usr/local/bin/ffmpeg -i /temp/video.avi -b 100 -vcodec mpeg4 -ar 22050 /final/video.mp4"

i can't seem to get that to work, i can run that command from the command line
i can run the php script from the command line and the file is output correctly
but when trying to run the command from a browser nothing happens

i can run a simple command like "ls" from the browser

i have tried chmodding everything to 777 but that didn't do anything
any ideas?
i've also tried chown, chgrp to apache for ffmpeg, but still nothing

safe_mode is off

[update]
nm, it was cos the original video file didn't have the permissions

thanks
dave

Last edited by dtra; 04-26-2005 at 02:33 AM.
 
Old 04-26-2005, 07:19 PM   #2
trickykid
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Registered: Jan 2001
Posts: 24,133

Rep: Reputation: 197Reputation: 197
Re: [php] accessing command line

Quote:
Originally posted by dtra
[update]
nm, it was cos the original video file didn't have the permissions
That's actually what I was going to suggest first while reading until I saw your update.

I think another way of doing this or running the command would be something like this so its all in one line and you wouldn't need to have the separate exec line:

Code:
$execVideo = system(''/usr/local/bin/ffmpeg ' . '$flags'');
Or something along those lines.. might even make your code look cleaner if you setup a variable for the path of the command or so on..

Cheers.
 
  


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