Help on GREP

pgb_710 · 08-23-2007, 05:33 AM

hi,

I want to grep the output between two patterns.
Ex: I have test file as follows:

$ cat test.txt
10.04 AM memory allocated
10:12 AM log started.
10:14 AM Table1 loaded.
10.24 AM Table2 loaded.
10.56 AM log stopped.
10.59 AM memory released.

I want the activities carried out between Log started and Log stopped using
GREP command.
I tried various combnation how ever failed to retrieve exact output.

I want following output:

10:14 AM Table1 loaded.
10.24 AM Table2 loaded.

colucix · 08-23-2007, 05:46 AM

I'd use sed, instead

Code:

sed -n '/log\ started/,/log\ stopped/p' test.txt | sed '1d' | sed '$d'

probably there is a better way... I'm not a sed guru!

pgb_710 · 08-23-2007, 07:04 AM

Quote:

Originally Posted by colucix

I'd use sed, instead

Code:

sed -n '/log\ started/,/log\ stopped/p' test.txt | sed '1d' | sed '$d'

probably there is a better way... I'm not a sed guru!

Thanks much its working as expected..

colucix · 08-23-2007, 07:52 AM

You're welcome! Take in mind that the first sed extracts lines between the two regular expressions, the second and the third sed commands in the pipeline remove the first and the last line of the output, respectively. So, if you have more than one block starting with "log started" and ending with "log stopped", the lines containing these two strings - in the middle - will not be removed.