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Old 11-18-2005, 07:13 PM   #1
NullDevice23
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Registered: Feb 2005
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[SOLVED] Permissions with umask


hi,

if i type

Code:
$ umask 002
$ touch hello
$ ls -l
-rw-rw-r--   1 myname mygrp      0 Nov 19 02:16 hello
The umask is what u subtract from a octal chmod value right? Where is the "x" execute then? I set it to 0 for owner and group, they still dont have the execute permission set.

-> ?? Why

Last edited by NullDevice23; 11-18-2005 at 07:47 PM.
 
Old 11-18-2005, 07:27 PM   #2
AltF4
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Registered: Sep 2002
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Distribution: SuSE, Knoppix
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because by default files are not executable - would be pretty useless to have all text files, jpg files, etc. executable :-)

you have to "chmod +x" or use a program being "clever" enough to know it creates executble files (e.g. gcc :-) to set the "x" bit.
 
  


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