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Old 08-18-2012, 02:16 PM   #1
zsh
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Registered: Aug 2012
Location: Russia
Distribution: Slackware
Posts: 3

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xargs --replace or -I options


Where is a wrong?
Code:
xargs -I{} foo {} bar/$(basename {})
Instead of the substitution
Code:
$(basename /full/path)
it seems to that basename applied to {}

Thanks!
 
Old 08-18-2012, 02:27 PM   #2
David the H.
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Registered: Jun 2004
Location: Osaka, Japan
Distribution: Debian sid + kde 3.5 & 4.4
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"$()" is not a system command, but a shell syntax pattern that runs the command in a subshell. xargs is not a shell, so it cannot execute it. It should be possible by having it execute "bash" or another shell, with the code as the argument to that.

BTW, it may help if you provided more details about what you are trying to do, such as what the input to this command should be, and/or what you want to get out of it.
 
1 members found this post helpful.
Old 08-18-2012, 04:17 PM   #3
zsh
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Registered: Aug 2012
Location: Russia
Distribution: Slackware
Posts: 3

Original Poster
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I tried to form arguments of the command convert from imagemagick package in this way

Code:
find somedir ... | xargs -I{}  convert {}  -resize 50% destdir/$(basename {})
Now to avoid error I refused from direct transfer from find to xargs via pipe

Solution looks like
Code:
list=$(find ...)
for i in $list
do
   convert $i -resize 50% destdir/$(basename $i)
done
Thanks for the help

Last edited by zsh; 08-18-2012 at 04:29 PM.
 
  


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