will it be poosile to sort the output of ls command based on timestamp of files.
 

Hello All,

Problem, i have some files under a directory say /home/user.

i want to pick up the file which has the latest timestamp.

for eg:
content of the directory is something like this
-rw-r--r-- 1 root other 0 Sep 15 11:26 3.5.0.13.0.daily_sol
-rw-r--r-- 1 root other 0 Sep 15 11:26 3.5.0.13.0.daily_linux
-rw-r--r-- 1 root other 0 Sep 15 11:26 3.5.0.13.0.daily_hpux
-rw-r--r-- 1 root other 0 Sep 15 11:26 3.5.0.13.0.daily_hpia64
-rw-r--r-- 1 root other 0 Sep 15 11:26 3.5.0.13.0.daily_aix
-rw-r--r-- 1 root other 0 Sep 15 11:26 3.5.0.13.0.7_linux
-rw-r--r-- 1 root other 0 Sep 15 11:26 3.5.0.13.0.7_hpux
-rw-r--r-- 1 root other 0 Sep 15 11:26 3.5.0.13.0.7_hpia64
-rw-r--r-- 1 root other 0 Sep 15 11:27 3.5.0.13.0.7_aix
-rw-r--r-- 1 root other 0 Sep 15 11:30 3.5.0.13.0.7_sol

my requirement here is when i give command
ls -lrt 3.5.0*_sol, it will return

-rw-r--r-- 1 root other 0 Sep 15 11:26 3.5.0.13.0.daily_sol
-rw-r--r-- 1 root other 0 Sep 15 11:30 3.5.0.13.0.7_sol

from this output i want to pickup the file which is latest in term of date or time. in this case this is the one 11:30 3.5.0.13.0.7_sol

is there any option in ls command itself only to list based on timestamp.

Thanks,
Shadman

see the -t switch;
ls -lt ( to see fname & other items)
ls -t (just filename)
http://linux.die.net/man/1/ls