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Old 04-06-2010, 12:54 PM   #1
Snake_Eyes_
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Registered: Dec 2009
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Why does `wc -m` output one too many?


# echo "foobar" > /tmp/word
# cat /tmp/word | wc -m
7

I want to print the number of characters in the file.
Why does it output 7? Am I missing something obvious?

manpage:
-m, --chars
print the character counts
 
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Old 04-06-2010, 01:02 PM   #2
Fingers of Fudge
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Maybe there's an end of file character.
 
Old 04-06-2010, 01:54 PM   #3
tredegar
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Registered: May 2003
Location: London, UK
Distribution: Debian "Jessie"
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Quote:
Maybe there's an end of file character.
It is is a <NL>:
Code:
tred@pc:~$ echo "foobar" > /tmp/word
tred@pc:~$ hexdump /tmp/word
0000000 6f66 626f 7261 000a
=        o f  b o  r a   <NL> 
=        f o  o b  a r   <NL> when you have byte-swapped
Try it again with echo -n "foobar" > /tmp/word

Code:
man echo....
DESCRIPTION
       Echo the STRING(s) to standard output.

       -n     do not output the trailing newline
 
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Old 04-06-2010, 02:03 PM   #4
Snake_Eyes_
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Awesome!!!! Works, thanks.
 
  


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