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I really don't understand the purpose of your command
Let's analyze it. You first tell echo to write textually this string:
Then you tell it to write a backslash, one of them is consumed to scape the second one, that's why only one is printed. The slashes and the 'z' are out of the quotation marks, so they are not inmune to the shell interpretation, and that's why they are not printed literally. So, you got only one slash, and the 'z'.
At the end, you have included this (which makes absolutely no sense in this context).
Two single quotes, with an empty string inside...
This definitely looks as homework, and you should be reading the provided links and the bash man page the first thing. Read the QUOTING section in the bash man page. Everything you need is there.
I took the liberty to merge your two directly related
threads and would ask that you stick with one in the
future .... re-visit the rules, specifically the bit about
double-/cross posting and stick to it.