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Old 12-18-2007, 01:46 PM   #1
danielj28
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What does the $@ represent in a bash script?


I'm new to reading (and writing) bash scripts and I can't find any documentation for what the $@ parameter/variable represents and what value it receives. Please advise. Thanks.
 
Old 12-18-2007, 02:18 PM   #2
pwc101
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Quote:
Originally Posted by man bash
@ Expands to the positional parameters, starting from one. When the
expansion occurs within double quotes, each parameter expands to a
separate word. That is, "$@" is equivalent to "$1" "$2" ... If
the double-quoted expansion occurs within a word, the expansion of
the first parameter is joined with the beginning part of the orig-
inal word, and the expansion of the last parameter is joined with
the last part of the original word. When there are no positional
parameters, "$@" and $@ expand to nothing (i.e., they are
removed).
It means each argument supplied to the script from the command line:
Code:
pwc101@linux:> ./myscript argument_1 argument_2
$@ represents argument_1 and argument_2 in that example, which can be individually referenced as $1 and $2.

See http://db.ilug-bom.org.in/Documentat...es.html#APPREF for more info.
 
Old 12-18-2007, 06:37 PM   #3
danielj28
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Thanks

for the help!
 
Old 12-18-2007, 06:51 PM   #4
PTrenholme
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On most distributions the info command (in a terminal window) may be used to display information about a command. Did you try info bash?

If you're not familiar with the info command, try info info for an explanation.
 
Old 12-18-2007, 10:56 PM   #5
chrism01
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The nice version of the manual: http://www.tldp.org/LDP/abs/html/int...es.html#APPREF
 
  


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