wc -l command, only keeping the numbers

shoemoodoshaloo · 07-30-2009, 06:03 PM

Hey everyone,

I am writing a small script which has to take the number of lines in a file, divide it by two, and store it as a variable:

I first tried to store the number of lines in a file with:

Code:

let MIDPOINT=`echo "wc -l $FILE"`

but realized that this will try to store the number of lines and the file name. How can I change this to store only the number of lines?

colucix · 07-30-2009, 06:17 PM

Code:

cat $FILE | wc -l

Passing the content of the file as standard input, there is no file name to display.

jay73 · 07-30-2009, 06:22 PM

numlines=$(($(wc -l filename | cut -d " " -f 1 -)/2))

colucix · 07-30-2009, 06:51 PM

Or something like:

Code:

MIDPOINT=$(awk 'END{print NR/2}' $FILE)

Tinkster · 07-30-2009, 07:01 PM

Code:

let MIDPOINT=`echo "wc -l < $FILE"`

shoemoodoshaloo · 08-03-2009, 03:02 PM

Thanks everyone.