variables
Hi all, just wondering if you can help - i have a program that works but now i want to prompt for username and use the store value, but it prompts but doesnt use the variable as far as i can see....
#!/bin/bash showMenu () { echo "1) Display user account on the laptop" echo "2) Display the bash history" echo "3) Does the Mozilla Firefox history log file exist" echo "4) quit" } var=username while [ 1 ] do showMenu read CHOICE case "$CHOICE" in "1") cat /etc/group |cut -d: -f1 ;; "2") cat /home/john403920394/.bash_history ;; "3") echo "Please enter a username: " read $username FILE=$1/home/$username/.mozilla/firefox/b7wuc85h.default/places.sqlite if [ -f $FILE ]; then echo "File $FILE this file does exist." else echo "File $FILE does not exist." fi ;; "4") exit ;; esac done Would appriciate any help - thank you |
remove the dollar sign from your read statement.
Code:
#!/bin/bash |
As demonstrated, please also use [code][/code] tags when displaying code to make it readable and keep formatting.
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