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Old 07-25-2012, 11:13 AM   #1
Paradigm6790
LQ Newbie
 
Registered: Jul 2012
Posts: 2

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Using zip to zip the contents of a directory to another?


Hello,

I am writing a tcl script that I use the zip command at the end to gather up the results of my scripts procedures into a zip file.

Let's say I have 2 paths:
/usr/whatever/tmp/startDir
/home/whatever/tmp/endDir

I am currently using:
Code:
exec zip -r /home/whatever/tmp/endDir /usr/whatever/tmp/startDir
The issue is that when I do this, while I DO get the contents of starDir, I also get the a folder structure in the zip file starting from /usr.

How do I get JUST the files in the startDir, and not the directories themselves?

Thanks!

Last edited by Paradigm6790; 07-25-2012 at 11:52 AM.
 
Old 07-25-2012, 11:33 AM   #2
Mr. Alex
Senior Member
 
Registered: May 2010
Distribution: No more Linux. Done with it.
Posts: 1,238

Rep: Reputation: Disabled
Code:
cd /usr/whatever/tmp/startDir
zip -r archive.zip *
Or you can put the archive to another directory (for instanse to your home):
Code:
cd /usr/whatever/tmp/startDir
zip -r ~/archive.zip *
If a directory contains hidden files, specify 'em like this:
Code:
zip -r archive.zip * .*
P. S. Wrap your code up with forum tags.

Last edited by Mr. Alex; 07-25-2012 at 11:45 AM.
 
Old 07-25-2012, 11:51 AM   #3
Paradigm6790
LQ Newbie
 
Registered: Jul 2012
Posts: 2

Original Poster
Rep: Reputation: Disabled
I get this error when trying to use the wildcard:

zip warning: name not matched: *

Edit: The error I was having was a TCL error. It ended up being more complicated than first anticipated in TCL, I had to iterate through a list. I ended up doing:
Code:
cd /usr/whatever/tmp/startDir
foreach f [glob *] {
	exec zip -r /home/whatever/tmp/endDir $f
}

Last edited by Paradigm6790; 07-25-2012 at 12:13 PM.
 
  


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