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I have a big file called the game, and want to find all the lines that do NOT have the word "shozbot" in it, and I want to sort them alphabetically, and save that in a file called "squiggy". How would I do that in one line of commands?

Thnks

Sorry, but it's hard to take your post seriously - with a subject of urgent and a task that sounds like it was made up... What have you done so far and what specific problem are you having?

Seriously, pick a more appropriate title for your post next time.

As for the command, here's a basic example (you'll need to add options depending on your requirements):

Code:

grep -v shozbot game.txt | sort > squiggy.txt

Win32sux has answered your question.

I give you some explanation here.

Code:

grep -v "pattern" fileName

prints lines that do not caontain the "pattern". If the "pattern" is not found at all then all the lines are printed.

Remove the -v option and it will print only those lines that contain at least one match of the "pattern".

So,

Code:

grep -v "shozbot" game

will print any line that does not contain "shozbot".

Next, we pipe this output to the sort command which displays the sorted lines:

Code:

grep -v "shozbot" game | sort

Finally, we redirect the sorted output to a named file:

Code:

grep -v "shozbot" game | sort > squiggy

Check it out!