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Old 04-09-2013, 08:22 PM   #1
lcarrick
LQ Newbie
 
Registered: Apr 2013
Posts: 1

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unix Scripting


I need help with scripting, im trying to get a user to enter two number between 1 and 5 and if they enter a number above 5 then i have to have a message show up that they have to enter a new number. then when they enter a number with in the ranges i have to add the numbers and divide by three. this is what i have so far.



case
echo "Please enter a number"
read num1
echo "Please enter a number"
read num2
if num1 -gt 5; then
echo "Please pick a number less than 5 for number 1"
else
echo "Thank you for entering number 1"
if num2 -gt 5; then
echo "Please pick a number less than 5 for number 1"
else
echo"Thank you for entering number 1"
esac
 
Old 04-09-2013, 09:42 PM   #2
jpollard
Senior Member
 
Registered: Dec 2012
Location: Washington DC area
Distribution: Fedora, CentOS, Slackware
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sounds like homework...

And you didn't read the book either, nor the manpage on bash (sh depending on system).
 
Old 04-09-2013, 10:03 PM   #3
chrism01
LQ Guru
 
Registered: Aug 2004
Location: Sydney
Distribution: Centos 6.9, Centos 7.3
Posts: 17,357

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Indeed; bookmark/read
http://rute.2038bug.com/index.html.gz
http://tldp.org/LDP/Bash-Beginners-G...tml/index.html
http://www.tldp.org/LDP/abs/html/

Incidentally, please use code tags https://www.linuxquestions.org/quest...do=bbcode#code
 
Old 04-10-2013, 05:29 AM   #4
grail
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Registered: Sep 2009
Location: Perth
Distribution: Manjaro
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I would be curious to know what you think the 'case' statement is doing for you?
 
  


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