UML image creation and using that as boot option
 

Hi All,
Recently I started working with UML(USER MODE LINUX). I am using Suse 11.3 with kernel version 2.6.34. But I downloaded the latest kernel 2.6.37.2 to create UML image on X86 ,32bit Intel platform.

I am able to "make" using the below commands
make menuconfig ARCH=um
make ARCH=um linux

After these It created two binaries of exact size with names linux and vmlinux.

I edited /boot/grub/menu.lst and /etc/grub.conf with tag name "UML linux 2.6.x"

When I booted I can see the option for booting UML, but when I tried to boot it ended up giving error:13 unsupported format.

I tried "make install ARCH=um" to create vmlinuz, but it failed with error No such target.
Next I tried with "make install", which created vmlinuz image but when booted again gave me Error 13: un supported format.

Can anyone help me if I am missing any thing.
If I need to use vmlinuz bin image , can any one suggest me creating this?