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thebeav 01-13-2011 04:55 PM
Trying to figure out a date command
 
Newbieness glaring brightly here :o Working through a Unix/Linux book trying to figure out the basics of the shell. I am trying to figure out how to run a command with bash to find the last day of the month in any given month. I read the man pages for date and cal but I am stupid or missing something. I figured out many things but this is the only one that has me pulling my hair out at this time. Thanks in advance.

tligda 01-13-2011 07:14 PM
Quote:
cal <month> <year> | sed '/^$/d' | tail -1 | awk '{printf $NF}'
via

jmc1987 01-13-2011 09:21 PM
Well what is it your trying to get? This is a example using the date command with a backup

tar cvzpf homebackup-`date +%m-%d-%y` /home/username

If you noticed I put the date command in ``. So give a little more info if this doesn't cover what you need

crts 01-13-2011 09:54 PM
Hi,

this, e.g., will also give you the name of the day:
Code:
cal feb 2000|sort -nr | awk 'FNR==1{a=NF;b=$NF}/^[^ [:digit:]]/{print $a,b}'
If this is not what you were looking for then you'll need to clarify a bit more.

thebeav 01-13-2011 10:31 PM
Thank you, now I have to digest this. Thanks for the help. Much appreciated.:)

for the last day of October
Code:
echo $(cal 10 2011) | awk '{print $NF}'
for the last day with of October including name of the day
Code:
cal 10 2011|sort -nr | awk 'FNR==1{a=NF;b=$NF}/^[^ [:digit:]]/{print $a,b}'

jmc1987 01-13-2011 11:56 PM
oops sorry OP i just realized I had misread your question.


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