Total particular files size in a directory

kirukan · 12-28-2009, 11:55 AM

Please give some idea, i need to count total size of files which were created in a particular date(Ex:-the files were created on Dec 25)

I have used following
#ls -l | grep "Dec 25" | du -k
I believe this is wrong
Note:- This is for Solaris 8 environment

GooseYArd · 12-28-2009, 01:09 PM

Quote:

Originally Posted by kirukan

Please give some idea, i need to count total size of files which were created in a particular date(Ex:-the files were created on Dec 25)

I have used following
#ls -l | grep "Dec 25" | du -k
I believe this is wrong
Note:- This is for Solaris 8 environment

ls -l | grep "Dec 25" | awk '{ SUM += $5} END { print SUM/1024/1024 }'

should do it.

You can also use the unix find command in place of ls and grep, but by the time you read the find manpage to figure out how to use the find time parameters, you could have finished the command with ls and grep already

kirukan · 01-03-2010, 11:47 AM

Quote:

ls -l | grep "Dec 25"

This also wont give us perfect size because if there is any subdirectories within the main direcoty, ls -l count subdirectories also, I just need only regular files size which were created on a particular date(Ex:- 25th December 2009 ).

In find command
#find * -type f -mtime 10, from today(3rd January 2010)
The above command may print the files which were created on 25th December 2009 (but it doesn't print, i don't know what mistake is there)
But as i have seen find command, it only print the files name so how can i calculate the total size?

Please anybody have idea?

colucix · 01-03-2010, 02:48 PM

Quote:

Originally Posted by kirukan

find * -type f -mtime 10

This does not print anything since you cannot use a wildcard as the search path: if you want to start your search from the current directory use a dot or if you want to start from another point, just use its full (or relative) path. For example, these ones are valid

Code:

find . -type f -mtime 10
find /usr/local -type f -mtime 10

Take in mind that the wildcard is expanded by the shell with all the (not hidden) items in the current directory and the resulting command line is a non-sense.

Another clue is that you will not find exactly the files last modified on December 25th using -mtime 10, first because if you subtract 10 days from 3rd of January you get the 24th of December, second because you have to consider the rounding effect of timestamp. Here is an explanation for the -atime predicate from the GNU find man

Code:

When find figures out how many 24-hour periods ago the file was last accessed,
any fractional part is ignored, so to match -atime +1, a file has to have been
accessed at least two days ago.

The GNU find has addressed the problem introducing the -daystart option, to match relative times from the 00:00 of the current day. Unfortunately you don't have this facility in solaris.

Regarding the total size calculation here are two methods (depending on what commands are available on your solaris box):

1) just use find and ls (using the -exec predicate) and sum the file sizes by piping the output to awk (as suggested by GooseYArd above)

Code:

find . -type f -mtime 10 -exec ls -l {} \; | awk '{sum += $5} END{print sum}'

2) if you have the GNU find (Solaris 8 provided a lot of GNU commands prepending a "g" to the command name) you can take advantage of the -printf predicate to print out just the file sizes:

Code:

gfind . -type f -mtime 10 -printf "%s\n" | awk '{sum += $1} END{print sum}'

Hope this helps.