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Old 04-28-2012, 07:57 AM   #1
UnixNewbie91
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Sorting GREP output


Hi

Have these two grep commands

for file in ~/webhits/*; do echo "$file: "$(grep $MONTH "$file" | grep -c $YEAR); done

for file in ~/webhits/*; do echo "$file: "$(grep $MONTH "$file" | grep $YEAR|cut -d" " -f 1,7|sort -u |wc -l); done

that produce outputs that look like:
/home/luke/webhits/bluray.hits: 8
/home/luke/webhits/books.hits: 7
/home/luke/webhits/cds.hits: 6
/home/luke/webhits/computing.hits: 7
/home/luke/webhits/dvds.hits: 7
/home/luke/webhits/gadgets.hits: 3
/home/luke/webhits/games.hits: 8
/home/luke/webhits/garden.hits: 5
/home/luke/webhits/home.hits: 3
/home/luke/webhits/index.hits: 24
/home/luke/webhits/jewellery.hits: 5
/home/luke/webhits/kitchen.hits: 4
/home/luke/webhits/posters.hits: 4
/home/luke/webhits/shoes.hits: 4
/home/luke/webhits/watches.hits: 4

Just wondering how to sort them by numeric order

Thanks in advance
 
Old 04-28-2012, 10:01 AM   #2
David the H.
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Run the output through sort -n.

Edit: you probably need to sort by the number field only, so use "sort -n -k2" instead.

Last edited by David the H.; 04-28-2012 at 10:14 AM. Reason: corrected suggestion.
 
  


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