Show folder and only one subfolder using ls in command line
 

So I have many folders with many subfolders. All I want it to get the folder name and the first subfolder. I tried using ls -R but this give me more than I want it.

Let say I have:

dir1/subdir1/sub_1_1/file.a
dir1/subdir1/sub_1_1/file.a2
dir1/subdir1/sub_1_1/file.a3
dir1/subdir1/sub_1_1/file.a4
dir1/subdir1/sub_1_2/file.b
dir1/subdir2/sub_2_1/file.c
dir1/subdir3/sub_3_1/file.d
dir1/subdir4/sub_4_1/file.e
dir2/subdir1/sub_1_1/file.a
dir2/subdir1/sub_1_2/file.b
dir2/subdir2/sub_2_1/file.c
dir2/subdir3/sub_3_1/file.d
dir2/subdir4/sub_4_1/file.e
dir3/subdir1/sub_1_1/file.a
dir3/subdir1/sub_1_2/file.b
dir3/subdir2/sub_2_1/file.c
dir3/subdir3/sub_3_1/file.d
dir3/subdir4/sub_4_1/file.e
.
.
.

All I want when I execute the command is to show me:

dir1/subdir1
dir1/subdir1
dir1/subdir2
dir1/subdir3
dir1/subdir4
dir2/subdir1
dir2/subdir1
dir2/subdir2
dir2/subdir3
dir2/subdir4
dir3/subdir1
dir3/subdir1
dir3/subdir2
dir3/subdir3
dir3/subdir4
.
.
.

I don't think you can do that with ls, but you can with find:
--- rod.

That was my first guess but maxdepth or the depth option dont work .....give me an argument error

How about showing us the exact command you used? It sounds like you have a syntax error somewhere.

This should work in simple cases, but will throw an error if there are no subdirectories to match.
Note though that it's not advisable to parse ls for a script.

Which leads me to the big question...what do you need this for? If you tell us what your true goal is, it may be that there's a better solution.

Thanks that's what I wanted