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qerf	11-06-2005 03:41 PM

shell programming

i have to calculate mean value using shell programming.
ex:
./mean 11 15 18 19 41 45
but i cant succeed the getting arguments. The problem is count of arguments. I search web and see examples they are doing like that
n1=$1
n2=$2
n3=$3
...
..
but in my situation, number of arguments is unknown i mean, there will be only two or one hundred arguments. how cant i get arguments in this situation?
show me the rigth way thnx...

TBC Cosmo

11-06-2005 04:38 PM

Try using shift, described here

Andrew Benton

11-06-2005 04:48 PM

Code:

#!/bin/bash

for i in $*

do total=$(($total+$i))

echo $total

done

echo $(($total/$#))

Mad Scientist

11-06-2005 04:51 PM

Here's something that will work.

Code:

#!/bin/bash

# Compute the average of the numbers in file 'input'



SUM=0

NUM=0



for i in `sed -n p input`

do

let "SUM=$SUM+$i"

let "NUM=$NUM+1"

done



let "AVG=$SUM/$NUM"



echo $AVG



exit 0

You can name this file "avg". Then, place all the numbers you want to average in a file called "input", but make sure that there is only one number appearing on each line. For example, you could have a file "input" with the contents

Code:

And if you named your script "avg", and in the same directory you have the file "input" with the above contents, then from this directory can type

Code:

sh avg

and the number 3 should be printed to the terminal.

Mad Scientist

11-06-2005 04:54 PM

Whoops, Andrew got his in a few minutes before mine, and I didn't see it. His is simpler, and takes input more in the way you were asking for them.

Andrew Benton

11-06-2005 05:28 PM

Yes, but it doesn't do decimals, I had to use bc for that

Code:

#!/bin/bash

total=0

for i in $*

do

total=$(echo "scale=3; $total+$i" | bc)

done

echo "average="$(echo "scale=3; $total/$#" | bc)

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