if i do

cat /var/log/syslog | grep antip2p

i get a number of lines looking like this:
Dec 19 17:44:59 p2-266 kernel: antip2p IN=eth0 OUT= MAC=**:**:**:**:**:**:**:**:**:**:**:**:** SRC=222.88.173.5 DST=***.***.***.*** LEN=668 TOS=0x00 PREC=0x00 TTL=102 ID=30078 PROTO=UDP SPT=2244 DPT=1026 LEN=648

(the *:s is ofcourse not there originally)

if i would like it to look something like this:
Dec 19 17:44:59 SRC=222.88.173.5
what do I do?

is this possible to do in bash?

awk is the tool to use. you can select search terms, and format the output. example: the log file is x number of columns wide. you select which columns to print by specifying $1, $2, $3, etc, to indicate which columns to show.

feed the output of cat /var/log/syslog to awk via pipe.
cat /var/log/syslog | awk ' {antip2p print $3, $2, $4, $1, $5, $9, $7, $8, $6}' , or something along those lines. As you can see, the order of the columns to print can be specified to your liking.

PS: I probably have a syntax error in the awk statement, but can't see it right off hand.

excellent

many thanks

will have to learn more about awk
can perhaps solve some more problems of mine