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Old 12-19-2004, 12:36 PM   #1
jonsag
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Registered: Dec 2004
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select certain subjects in syslog


if i do

cat /var/log/syslog | grep antip2p

i get a number of lines looking like this:
Dec 19 17:44:59 p2-266 kernel: antip2p IN=eth0 OUT= MAC=**:**:**:**:**:**:**:**:**:**:**:**:** SRC=222.88.173.5 DST=***.***.***.*** LEN=668 TOS=0x00 PREC=0x00 TTL=102 ID=30078 PROTO=UDP SPT=2244 DPT=1026 LEN=648

(the *:s is ofcourse not there originally)

if i would like it to look something like this:
Dec 19 17:44:59 SRC=222.88.173.5
what do I do?

is this possible to do in bash?
 
Old 12-19-2004, 01:01 PM   #2
bigrigdriver
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Registered: Jul 2002
Location: East Centra Illinois, USA
Distribution: Debian Jessie 8.4
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awk is the tool to use. you can select search terms, and format the output. example: the log file is x number of columns wide. you select which columns to print by specifying $1, $2, $3, etc, to indicate which columns to show.

feed the output of cat /var/log/syslog to awk via pipe.
cat /var/log/syslog | awk ' {antip2p print $3, $2, $4, $1, $5, $9, $7, $8, $6}' , or something along those lines. As you can see, the order of the columns to print can be specified to your liking.

PS: I probably have a syntax error in the awk statement, but can't see it right off hand.

Last edited by bigrigdriver; 12-19-2004 at 01:03 PM.
 
Old 12-19-2004, 01:05 PM   #3
jonsag
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Registered: Dec 2004
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excellent

many thanks

will have to learn more about awk
can perhaps solve some more problems of mine
 
  


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