[SOLVED] sed, awk, Keep only text between two regular expressions
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I see your problem comes from not reading man csplit. That comes from not having heard about csplit. If you wish, read posix csplit manual http://www.opengroup.org/onlinepubs/...es/csplit.html instead of GNU csplit manual. I doubt you meant that any POSIX-compliant utility is forbidden..
I have a directory of saved rss articles, all beginning with IS_*.
Each article has the top fields, then the body text, then a bunch of garbage at the bottome, links, etc.
My goal is to keep everything between the first blank line and a common phrase at the end of the article, and save all the articles to one file.
could you please copy and paste here a passage from one of your
and precede the beginning the passage you want to retrieve by
### scott_audio: beginning
and follow the last line of the passage by
### scott_audio: end
It would be easier to figure it out if I can have a look at the
Right off the bat it should be possible to do this via a script
shell that loops thru your files and run a sed script on them.
synss, hi, and thank you very much. Was exactly what I was looking for, a good solid example of what I was trying to accomplish... i made my loop, piped the final through sed '/./,/^$/!d' to take any double blank lines and tr -d '\n' to keep each paragrash one long line, and it worked perfectly. I'm reading up on what the double pipe means || ... looks like, though, it starts two lines down from the line that starts with 'Link:' and prints all the lines until it encounters 'Want podcasts...'
I've learned a lot and had fun, thanks again all
#better put in an absolute path for this
find $JEFF/* | while read f
if [ -d $f ]; then
#only process file if it is of type IS_something.txt
if [ "$ext" == "txt" ] && [ $(echo "$name" | grep -c '^IS_') -gt 0 ]; then
output="$dir/""$(echo $name | tr '[:upper:]' '[:lower:]')".rtf
$SEDER $input > $output
######## end of shell script ##################