All -

I'm trying to use grep to find out if file in a ksh script contains the following string:

'spdsnsrv -listenport'

this string is contained in a ksh shell variable see code below:

spds1="'spdsnsrv -listenport'"

while [[ $count -le 3 ]]; do

spds_pid=spds"${count}"

eval grep \$${spds_pid} $PSFILE > /dev/null
...
((count=count+1))

done

I get the following results:

grep: invalid option -- t
Usage: grep [OPTION]... PATTERN [FILE]...
Try `grep --help' for more information.
grep: invalid max count



I have tried it with double quotes around the string, single quotes around the string and no quotes around the string.

How can I fix this?

Best not to use eval and indirect vars, too fragile; use an array to store the values instead eg http://wiki.bash-hackers.org/syntax/arrays

you need to use fgrep (or grep -F), or grep -- 'spdsnsrv -listenport'

Pan64 et al -

I tried:

count=1

spds1="'spdsnsrv -listenport'"
spds2="'spdsserv -nameserverport'"
spds3="'spdssnet -listenport'"

echo spds1 = $spds1
echo spds2 = $spds2
echo spds3 = $spds3

########################################################################
# Get running Websphere process
########################################################################

ps -ef | grep spds > $PSFILE

while [[ $count -le 3 ]]; do

spds_pid=spds"${count}"

eval grep -- \$${spds_pid} $PSFILE > /dev/null

...
((count=count+1))
done

Here are the results:

spds1 = 'spdsnsrv -listenport'
spds2 = 'spdsserv -nameserverport'
spds3 = 'spdssnet -listenport'

grep: -listenport': No such file or directory
grep: -nameserverport': No such file or directory
grep: -listenport': No such file or directory


Any thoughts?

I do not understand that line at all. What is the goal of it?
eval grep -- \$${spds_pid} $PSFILE > /dev/null
I think you do not need eval (eval is not a really safe command) and you need to use "" to protect your pattern: grep -- "pattern" file