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Old 11-18-2004, 03:24 PM   #1
TroelsSmit
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Registered: Feb 2004
Location: Denmark
Distribution: Debian / Suse
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script finding files, placing them and naming the


Hi,
I would like to create a script which will do the following:

1. Find all files following a regular expression finging following names: *.img *.IMG *.jpg *.JPG *.eps *.EPS

2. Move these files to a specified directory naming them:
1filename
2filename
3filename
etc.
etc.

If this can be easily done (tcsh,bash,perl) please help :-)
 
Old 11-18-2004, 03:57 PM   #2
homey
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Here's a little bash diddy which may help.

#!/bin/bash
for i in *.jpg *.gif *.img
do
n=$(( $n + 1 ))
echo mv "$i" "/home/$n$i"
done
 
Old 11-18-2004, 10:14 PM   #3
TroelsSmit
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Perfect, but I would like it to search my entire structure from / and so forth ... can that be done ?
 
Old 11-18-2004, 10:45 PM   #4
btmiller
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I would use:

find / \( -name "*.jpg" -o -name "*.img" -o - name "*.eps \) -print

to find the files, and then use xargs to pipe them to a shell script like homey gave you to do the moving. So the final result is:

find / \( -name "*.jpg" -o -name "*.img" -o - name "*.eps \) -print | xargs move_script

Then change the for loop in the script to "for i in $@" ($@ is all the arguments in bash).
 
Old 11-18-2004, 10:50 PM   #5
homey
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Quote:
Perfect, but I would like it to search my entire structure from / and so forth ... can that be done ?
You can do this from the / if you want but normally something like that would be for renaming a bunch of pics in your images directory. If you want to run this from the root directory, I would not try to move ( mv ) all of those files but use copy ( cp ) instead.

#!/bin/bash
for i in *.jpg *.gif *.img
do
n=$(( $n + 1 ))
echo cp "$i" "/home/$n$i"
done
 
  


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