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Old 09-16-2004, 11:26 AM   #1
linux_ub
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Registered: May 2004
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renaming batch of files


hi

i need some help renaming a batch of files

the original files are spread around a few directories with overlapping names

eg. /image1/file1.jpg
/image1/file.jpg
/image2/file.jpg
/image2/file1.jpg
/image2/file2.jpg
/image3/file1.jpg


i need the files in this format

/image/file001.jpg
/image/file002.jpg
/image/file003.jpg
/image/file004.jpg
/image/file005.jpg
/image/file006.jpg

i need the number in the new files to be a exactly 3 digits. i am sure tht i dont have more than 999 files

thanks a lot for ur help
 
Old 09-16-2004, 03:37 PM   #2
Tinkster
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Ummm ... that will be scripting :)


Cheers,
Tink
 
Old 09-16-2004, 03:50 PM   #3
realjustin
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www.tldp.org/LDP/abs/abs-guide.pdf

That is the best bash scripting guide I know of. Read it and you'll have no issues. You're looking for a slightly less trivial script than what you are probably ready for, so this guide will prepare you well.
 
Old 09-16-2004, 04:22 PM   #4
chrism01
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You'll have to generate the leading zeroes yourself. Use ${#var} syntax as exampled on this page: http://tille.soti.org/training/bash/ch10s03.html
 
Old 09-17-2004, 04:22 AM   #5
theYinYeti
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I did not test, but it should give you a start, if not all-done:
Code:
#!/bin/bash
# $1 (optional): file mask (eg: "*.gif"), else "*.jpg" assumed
# $2 (optional): file prefix (eg: "file"), else "file" assumed
# $3 (optional): destination dir (eg: "~/images"), else "$HOME" assumed
# $4 (optional): ':'-separated list of directories
#                (eg: "/mnt/img1:/mnt/img2"), else "." assumed
# Files named like ${1} in directories ${4} will be copied to ${3}
# with name ${2}000 ... ${2}999 (maximum) with same extension as ${1}

if [ -z "$1" ]; then
	echo "File mask (first parameter) must be given." >&2
	exit 1
fi

MASK="${1:-\*.jpg}"
EXT="${MASK##*.}"
[ -n "$EXT" ] && EXT=".$EXT"
FPFX="${2:-file}"
DEST="${3:-$HOME}"
DIRS="${4:-.}"
DIRS="$(echo "$DIRS" | sed 's|:|\n|g')"
NUM=0

if [ ! -d "$DEST" ]; then
	mkdir -p "$DEST" || ( \
	echo "Destination directory (second parameter) is not valid." >&2
	exit 1)
fi
DEST="$(cd "$DEST" && pwd)"

function formatNum() {
	local result="$1"
	while [ ${#result} -lt $2 ]; do
		result="0$result"
	done
	echo "$result"
}

echo "$DIRS" | while read DIR; do
	if [ -d "$DIR" ]; then
		DIR="$(cd "$DIR" && pwd)"
	else
		echo "Directory $DIR skipped. It does not exist." >&2
		continue
	fi
	if [ -z "${DEST##${DIR}/*}" ]; then
		echo "Directory $DIR skipped. It contains the destination." >&2
	fi
	find "$DIR" -type f -iname "$MASK" -print
done | while read FILE; do
	NUM2=$(formatNum $NUM 3)
	while [ -e "${DEST}/${FPFX}${NUM2}${EXT}" ]; do
		NUM=$(( $NUM + 1 ))
		NUM2=$(formatNum $NUM 3)
	done
	cp -f "$FILE" "${DEST}/${FPFX}${NUM2}${EXT}"
done
Yves.
 
Old 09-17-2004, 01:11 PM   #6
chrism01
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Actually, for nums you could prob use:
myvar=`printf "%03d\n" $oldvar`
 
Old 10-27-2004, 10:41 PM   #7
xplasma
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if u lazy u can use this

I know some of us dun have the time to read a whole book just to figure out how to batch rename some files

BTW That pdf rocks, i highly recommend it for anyone who wants to know more about bashing ..

I was browsing around and found this program Krename It rocks for batch renaming !@
Maybe use it as alternative while your learning how to do it by your own code .. Anyway thought id help out alil ..
 
  


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