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Now i wanna write a regular expression pattern to match all the words
I tried
Code:
cat test | grep -r M[uo]'*am+[ae]r\s[aAG]l*-*Q*K*ad+h*afi
But it doesnt work
if i try
cat test | grep -r M[uo] ...till here it works..
Any suggestion ? The regular expression checker online says that the expression is ok.. So whats the problem?
Like said, escape the quotation mark. By itself it may start a quoted piece of characters, but it never stops (no ending quote).
See this for example:
Code:
echo "foo'bar" |grep \'
(GNU grep 2.6.3)
Edit: not that it means anything, but the original post, without explanations, does have a little questionable tone to it, taking into account the current situation. It wouldn't harm if you explained a little more what you're trying to achieve in general; if it's just technical stuff with regular expressions and/or matching in general, you could work this with more general strings (the so-called "minimal working example"). This is not, after all, a political forum.
Not to be too picky, but without relevance to what you do not want, ultimately the simplest answer (apart from any character on a line as you want all lines),
would be:
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