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Old 06-13-2014, 06:38 AM   #1
jonnybinthemix
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Registered: May 2014
Location: Bristol, United Kingdom
Distribution: RHEL 5 & 6
Posts: 169

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Quick BASH Question


Hey Guys,

Just a real quick BASH question that I'm sure will be simple but it's holding me up from testing something relating to the other threat I've got...

If I have a list of file locations in a variable, how can I print the contents of that variable into a copy command?

For example:

cat $FILES would display:

./file1
./file2

But in the script I'd like to do something like
Code:
cp file1 file2 /tmp
I've tried:

Code:
cat $FILES | cp - /tmp
Code:
 
cat $FILES | cp <&1 /tmp
Code:
cp $FILES /tmp
none of the above work and I can see why.. but is there something that I'm missing?

Thanks
Jon
 
Old 06-13-2014, 06:46 AM   #2
pan64
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Registered: Mar 2012
Location: Hungary
Distribution: debian i686 (solaris)
Posts: 8,491

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cp cannot accept any input from stdin, therefore piping into cp has no any meaning.
You can try cp $(cat $FILES) /tmp
 
2 members found this post helpful.
Old 06-13-2014, 08:55 AM   #3
jonnybinthemix
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Registered: May 2014
Location: Bristol, United Kingdom
Distribution: RHEL 5 & 6
Posts: 169

Original Poster
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Thanks that worked

Appreciate your help.
 
  


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