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Old 02-16-2015, 07:26 PM   #1
wtdedula
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Question about partitioning a 4TB drive


Hello All;
I am building a Linux media server in my home and I am new to Linux.

Right now I am at the point where I am partitioning and formatting each of my 4TB drives.

I ran sudo parted on /etc/sdb
Then I set mklabel to gpt.

Now my question is about mkpart.

In order to use the full 4TB disk for data (Only one partition)

Do I set mkpart primary 0GB 3725GB
or
do I set mkpart primary 0GB 4000GB?

I don't want to enter a larger capacity than my disk will allow but I also want to be sure I am taking advantage of all of the available space.

Thanks.

Tim
 
Old 02-16-2015, 08:34 PM   #2
syg00
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Parted is (now) pretty smart - do what you think will work; maybe better to use 0% and 100%; saves all the algebra angst.
Start it with "-a optimal" to force alignment.

Last edited by syg00; 02-16-2015 at 09:04 PM. Reason: removed primary comment
 
Old 02-16-2015, 09:35 PM   #3
jefro
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Hello and welcome to LQ.
 
Old 02-16-2015, 11:24 PM   #4
John VV
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Quote:

In order to use the full 4TB disk for data (Only one partition)
well it is YOUR hardware

i would use 4 partitions

but for a big drive and ONE partition ( 4 tb's is big )
you need to use GPT
then a rather NEW!!!! operating system with a new version of fdisk

older versions of fdisk and parted or gparted can NOT read the GPT partition table

Last edited by John VV; 02-16-2015 at 11:28 PM.
 
Old 02-18-2015, 11:01 AM   #5
Shadow_7
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You need to use the GPT partitioning scheme for drives > 2TB. With various quirks when you do use GPT depending on the age of your utilities.
 
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Old 02-18-2015, 06:57 PM   #6
syg00
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Not true.
If you need partition(s) greater than 2G you need gpt - but a 4G disk may be partitioned to multiples each less than 2G using classic MBR partitioning.
 
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Old 02-18-2015, 09:02 PM   #7
rknichols
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Quote:
Originally Posted by syg00 View Post
Not true.
If you need partition(s) greater than 2G you need gpt - but a 4G disk may be partitioned to multiples each less than 2G using classic MBR partitioning.
How is that MBR partition table going to represent, in its 32-bit fields, the starting or ending LBA of a partition that lies beyond the 2TB boundary?
 
Old 02-18-2015, 09:12 PM   #8
syg00
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Excellent question. My apologies to @Shadow_7.
 
Old 02-19-2015, 11:32 AM   #9
maples
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Quote:
Originally Posted by syg00 View Post
Not true.
If you need partition(s) greater than 2G you need gpt - but a 4G disk may be partitioned to multiples each less than 2G using classic MBR partitioning.
I think you mean TB... I've never had any issues using MBR on any of my disks, and all of my partitions are greater than 2GB.
 
  


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