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Old 11-17-2005, 11:11 PM   #1
evolutionspeak
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Question about makefiles


How could I make a command that would remove all the executables in the current directory without listing all of the executables explicitly?
 
Old 11-18-2005, 12:05 AM   #2
Dark_Helmet
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Two ways come to mind. The first is not a Makefile-ish style:
Code:
find . -type f -perm +111 -maxdepth 1 -exec rm -f {} \;
Of course, man find for details on the options, but that basically just deletes any file in the current directory (not sub-directories) that has any execute permission bit set (owner, group, or other). You can slap that command into the Makefile just like you would any other command. I'd personally verify its accuracy before using it though... Try using it on a backup copy of your development environment until you're confident it works as expected.

The second would be more in line with Makefile standards/form/guidelines. Create a TARGETS variable or something like that. Put in the explicit list of executable to delete in that variable. Then do an "rm $(TARGETS)" later. Depending on your setup, you might be able to do clever things such as automatic extension swapping. What I mean is, I've seen some Makefiles store all the object files into an OBJS variable, and then create a TARGETS (or similarly named variable) by using a Makefile syntax that dropped the ".o" extension from the OBJS variable. I'm no Makefile expert and can't tell you what the syntax is, but I know it's possible.
 
Old 11-18-2005, 12:08 AM   #3
evolutionspeak
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Thanks a bunch, I will give it a try.
 
  


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