LinuxQuestions.org - Problems trying to extract gzipped archives from script

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Problems trying to extract gzipped archives from script

ose.tar.gz: command not found
build.tar.gz: command not found
how to overcome this error? I am totally new to linux.

Those are data files, not cmds.
What exactly are you trying to do?

You should read this
http://rute.2038bug.com/index.html.gz

Can you tells us the name of your Linux version?
Please post the results of

Code:

cat /etc/*release*



uname -a



df -h

These are archived files (or a collection of zipped files). Tar stands for tape archive and gz for gzip.
These files were created as:

Code:

~$ tar -cvf ose.tar /path/to/source

~$ gzip ose.tar

So in order to check it's content, use:

Code:

~$ tar -ztvf ose.tar.gz

To open/extract it:

Code:

~$ tar -zxvf ose.tar.gz

OR

~$ gunzip ose.tar.gz

~$ tar -xvf ose.tar

Thanku for the reply

I have another problem. I am totally new to linux. I have been given one document and in that the paths are like this i.e./home/cdot/c4/ose. My mam has asked me to replace the path i.e. /home/cdot/ with some variable. How could I do this?

Thanku

Code:

$ var=/home/cdot

where var is a variable, it could be anything.
if you call the variable using echo, the output is what you have stored in the variable, right now it is path.

Code:

$ echo $var

output

Code:

/home/cdot

You can use $var instead of /home/cdot in your script

Thanku for the reply but still its not working.
Here is the error which i am getting.
./script: line 11: /home/cdot/c4/ose/site: is a directory
./script: line 12: /home/cdot/c4/ACE_wrappers/TAO: is a directory
./script: line 13: =/home/cdot: No such file or directory
[root@hpv2k-57 c4]# pwd
/home/cdot/c4
Thanku

Do you want to replace /home/cdot/ string with some variable...?

Code:

~$ sed -e 's/\/home\/cdot/<some_value>/g' infile.txt

OR

~$ gawk '{gsub(/\/home\/cdot\//,"<some_value>",$0); print $0}' infile.txt

Where, <some_value> is what you will replace /home/cdot with.

Probably best if you show us the script and be clear on what you want to see before and after.

I have been given one code and I have been asked to grep /home/cdot/c4 path in the code. Some where in the Makefiles this path is hardcoded. I have to find those paths and document it. Then I
have to replace those path with the variable where one can specify the path from my
script. I am unable to do dis.

I have found the path and it is
OSE_ROOT=/home/cdot/c4/ose and the other path is
export OTCommon_ROOT=home/cdot/c4/core/common

I have to replace only home/cdot with the variable.
Thanku

Thanku chris
This is the kind of script. Its not the exact script
My mam has asked me to search for the path /home/cdot/c4 nd replace /home/cdot with some variable so that it could be assessed by that variable instead of the directory.
export ROOT=`pwd`
export ACE_ROOT=$ROOT/ACE_wrappers
export LD_LIBRARY_PATH=$ACE_ROOT/lib
export TAO_ROOT=$ACE_ROOT/TAO
export PATH=$PATH:/$ROOT/build
gunzip ose.tar.gz
tar -xvf ose.tar
cd $ROOT/ACE_wrappers/ace
ln -s config-linux.h config.h
cd $ROOT/ACE_wrappers/include/makeinclude
ln -s platform_linux.GNU platform_macros.GNU

cd $ROOT/dc/jobs/unix
chmod +x bldsixax
./bldsixax release

mkdir $ROOT/core/UCA/release/lib
mkdir $ROOT/core/UCA/release/lib/i686-pc-linux_dbg.GNU3_4_4
$ROOT/core/OpenSDF/SDF/SDF_SchemaCompiler/src/SDF_Schema.cc
cd $ROOT/core/OpenSDF
export INSTALL_ROOT=$ROOT/core/OpenSDF
export PROJECT_PATH=$ROOT/core/OpenSDF

cd $ROOT/core/Common
cd $ROOT/core/CASGCommon
export INSTALL_ROOT=$ROOT/core/CASGCommon
ln -s dotproject.project
cd $ROOT/core/UCA
export INSTALL_ROOT=$ROOT/core/UCA
ln -s dotproject.project
grep /home/cdot/c4

---------- Post added 03-05-13 at 02:12 PM ----------

Thanku shivaa

No need to use any other variable. The $HOME in-build variable is enough to hold /home/cdot directory.

Else you can do following in your script:

Code:

VAR="/home/cdot/c4"

Then you can use this, as:

Code:

cat $VAR/foo.txt

OR

cd $VAR/bar

To make changes in your script, once invoke:

Code:

~$ gawk '{gsub(/\/home\/cdot\/c4/,"\$VAR",$0); print $0}' myscript.sh

Can you please suggest me some link or book for studying an practicing the scripts..
Thanku

Best reference books are here.

Please Mark the thread as solved, if you think it has so (option is under Thread Tools on top menu).

problem while replacing a directory with the variable

There are some scripts made in the path root/c4/build and in that scripts we have used the path /home/cdot/c4. So i want to replace /home/cdot path with some variable. Rightnow I am acccessing my scripts from root/c4. I want to write a script in root so dat in the scripts, home/cdot path gets replaced with that variable. How can I do that?

Thanku.